Question For what value of k will the following linear system have infinitely many solutions? 2a+b=-6, 6a+kb=-18
There are infinitely many solutions to a linear equation with the same variable term on both sides of the equation. We have to find the coefficient of “b” from first equation: 2a + b = -6 b = -6 – 2a from second equation: 6a + kb = -18 b = (-18 – 6a)/k solve them simultaneously: (-18 – 6a)/k = -6 – 2a (-18 – 6a)/(-6 – 2a) = k k = 3 Reply