for the arthritic sequence 5,9,13,17,21,… how many terms would you need to get to 129 July 25, 2021 by Helga for the arthritic sequence 5,9,13,17,21,… how many terms would you need to get to 129
9514 1404 393 Answer: 32 Step-by-step explanation: The first term is 5 and the common difference is 9-5=4, so the n-th term is … an = a1 +d(n -1) an = 5 +4(n -1) = 4n +1 Then the term number for the term 129 is … 129 = 4n +1 . . . . . put the given value in the formula 128 = 4n . . . . . . . subtract 1 32 = n . . . . . . . . . .divide by 4 The 32nd term is 129. Reply
9514 1404 393
Answer:
32
Step-by-step explanation:
The first term is 5 and the common difference is 9-5=4, so the n-th term is …
an = a1 +d(n -1)
an = 5 +4(n -1) = 4n +1
Then the term number for the term 129 is …
129 = 4n +1 . . . . . put the given value in the formula
128 = 4n . . . . . . . subtract 1
32 = n . . . . . . . . . .divide by 4
The 32nd term is 129.