Question Find two triangles with the given angle measure and side lengths. Round side lengths to the nearest tenth and angle measures to the nearest degree. A = 61°, a = 14, b = 15

Answer: its A Step-by-step explanation: b^2 = 6^2 + 11^2 – 2*6*11cos 109 = 199.97 b = 14.1 to nearest tenth. now use sine rule to find the value of < A 14.14 / sin 109 = 6 / sin A <A = 24 degrees <C = 180 – 24 – 109 = 47 degrees <3 Reply

Answer:Step-by-step explanation:The right answer is A