Question

Find two triangles with the given angle measure and side lengths. Round side lengths to the nearest tenth and angle measures to the nearest degree.
A = 61°, a = 14, b = 15

Answers

  1. Answer:
    its A
    Step-by-step explanation:
    b^2 = 6^2 + 11^2 – 2*6*11cos 109  =   199.97
    b =  14.1  to nearest tenth.
    now use sine rule to find the value of < A
    14.14 / sin 109 = 6 /  sin A
    <A =  24 degrees
    <C = 180 – 24 – 109  = 47 degrees
    <3

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