Question Find there consecutive even integers such that the sum of smallest number and twice the middle number is 20 more then the largest number

Here is your answer let the numbers be x,x+2,x+4 so,the equation is x+2(x+2)=x+4+20 3x+4=x+24 2x=20 x=10 therefore the nos. are 10,12,14 Hope This Helps Reply

Answer: The numbers are 10, 12, and 14 Step-by-step explanation: x + 2(x+2) = x+4 + 20 x = 10 So the numbers are 10,12,14 Reply

## Hope This Helps

Answer:Step-by-step explanation: