Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.) f(x)
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The value of c by the Mean Value Theorem for Integrals for the function over the given integral is 6.25.In the question, we are asked to find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function f(x)=5√x,[4,9] over the given interval.The given function is f(x)=5√x,[4,9].First we calculate the function value at the endpoints of the interval.f(4) = 5√4 = 5*2 = 10.f(9) = 5√9 = 5*3 = 15.We substitute x = c in the given function, to get:f(c) = 5√c.Now, we calculate f'(c) using the formula:f'(c) = (f(b) – f(a))/(b – a),or, f'(c) = (f(9) – f(4))/(9 – 4),or, f'(c) = (15 – 10)(9 – 4),or, f'(c) = 5/5 = 1.Differentiating the original function, gives us f'(x) = 5/(2√x).Substituting x = c in this gives us f'(c) = 5/(2√c).Equating this to f'(c) = 1 gives us:5/(2√c) = 1,or, √c = 5/2,or, c = 25/4,or, c = 6.25.Thus, the value of c by the Mean Value Theorem for Integrals for the function over the given integral is 6.25.Learn more about the Mean value theorem athttps://brainly.com/question/17111829#SPJ4The provided question is incomplete. The complete question is:“Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.)f(x)=5√x,[4,9].”