Question

Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.) f(x)

Answers

  1. The value of c by the Mean Value Theorem for Integrals for the function over the given integral is 6.25.
    In the question, we are asked to find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function f(x)=5√x,[4,9] over the given interval.
    The given function is f(x)=5√x,[4,9].
    First we calculate the function value at the endpoints of the interval.
    f(4) = 5√4 = 5*2 = 10.
    f(9) = 5√9 = 5*3 = 15.
    We substitute x = c in the given function, to get:
    f(c) = 5√c.
    Now, we calculate f'(c) using the formula:
    f'(c) = (f(b) – f(a))/(b – a),
    or, f'(c) = (f(9) – f(4))/(9 – 4),
    or, f'(c) = (15 – 10)(9 – 4),
    or, f'(c) = 5/5 = 1.
    Differentiating the original function, gives us f'(x) = 5/(2√x).
    Substituting x = c in this gives us f'(c) = 5/(2√c).
    Equating this to f'(c) = 1 gives us:
    5/(2√c) = 1,
    or, √c = 5/2,
    or, c = 25/4,
    or, c = 6.25.
    Thus, the value of c by the Mean Value Theorem for Integrals for the function over the given integral is 6.25.
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    The provided question is incomplete. The complete question is:
    “Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.)
    f(x)=5√x,[4,9].”

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