Find the value of y in the following system of equations.
21x – 7y + 512= 141
13x + 9y – 5z = -19
192 8y + 232 = 30
Question
Question
Find the value of y in the following system of equations.
21x – 7y + 512= 141
13x + 9y – 5z = -19
192 8y + 232 = 30
Answer:
21x – 7y + 512= 141 equals y= j^21x/7 + 53
13x + 9y – 5z = -19 equals y= -19/9 – 13x/9 + 5z/9
192 8y + 232 = 30 equals
x-3 = 6
4x=8
2x = 16
Answer:
y=3x+53
y=-19/9 -13x/9 +5z/9
Step-by-step explanation:
i only did one and two sorry:/