Question Find the value of y in the following system of equations. 21x – 7y + 512= 141 13x + 9y – 5z = -19 192 8y + 232 = 30

Answer: 21x – 7y + 512= 141 equals y= j^21x/7 + 53 13x + 9y – 5z = -19 equals y= -19/9 – 13x/9 + 5z/9 192 8y + 232 = 30 equals x-3 = 6 4x=8 2x = 16 Reply

Answer:21x – 7y + 512= 141 equals y= j^21x/7 + 53

13x + 9y – 5z = -19 equals y= -19/9 – 13x/9 + 5z/9

192 8y + 232 = 30 equals

x-3 = 6

4x=8

2x = 16

Answer:y=3x+53

y=-19/9 -13x/9 +5z/9

Step-by-step explanation:i only did one and two sorry:/