Question Find the three consecutive even integers such that one half of their sum is between 15 and 21. set up and solve a compound inequality.

The even integers are 10,12 and 14. Concept: An integer is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 5+1/2, and √2 are not. Let x,x+2,x+4 be the least, middle and greatest integer respectively. According to the question, 15< x+x+2+x+4< 21 (3x+6)/2> 15 and (3x+6)/2< 21 30< 3x+6 3x+6> 42 24<3x 3x<36 8<x x>12 x=10 x+2=12 x+4=14 Hence, The even integers are 10,12 and 14. For more information about integers, visit https://brainly.com/question/17695139 #SPJ4 Reply

even integers are 10,12 and 14.Concept:An integer is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 5+1/2, and √2 are not.even integers are 10,12 and 14.integers, visithttps://brainly.com/question/17695139#SPJ4