Find the three consecutive even integers such that one half of their sum is between 15 and 21. set up and solve a compound inequality.
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The even integers are 10,12 and 14.Concept: An integer is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 5+1/2, and √2 are not.Let x,x+2,x+4 be the least, middle and greatest integer respectively.According to the question,15< x+x+2+x+4< 21(3x+6)/2> 15 and (3x+6)/2< 2130< 3x+6 3x+6> 4224<3x 3x<368<x x>12x=10x+2=12x+4=14Hence, The even integers are 10,12 and 14.For more information about integers, visithttps://brainly.com/question/17695139#SPJ4