Question Find the length and width (in feet) of a rectangle that has the given area and a minimum perimeter. Area: 25 square feet

Length = 5 ft & width = 5 ft of a rectangle that has the given area . What is called rectangle? A Rectangle is a four sided-polygon, having all the internal angles equal to 90 degrees. The two sides at each corner or vertex, meet at right angles. The opposite sides of the rectangle are equal in length which makes it different from a square. Let the length and width of rectangle be x feet and y feet respectively. Give area = 25 feet² x y = 25 feet² y = 25/x feet² ………………1 Now let perimeter is p then p = 2 (x+y) = 2x + 2y p = 2x + 2 × 25/x P = 2X + 50/x diffrentiating w.r.t. x p’ = 2 – 50/x² ……………..2 putting p’ = 0 to find critical point 2 – 50/x² = 0 x² = 25 x = 5 [ x ≠ 5 ∴ length can not be negative ] Now, p” = 0 + 100/ x³ from (2) checking value of p” at critical point p” at x = 5 = 100/(x)³ > 0 Hence, perimeter is minimum at x = 5 ft putting x = 5 in equation 1 y = 1 Hence, length = 5 ft width = 5 ft Learn more about rectangle brainly.com/question/20693059 #SPJ4 Reply

Length = 5 ft & width = 5 ftof arectanglethat has the given area .What is called rectangle?Rectangleis a four sided-polygon, having all the internal angles equal to90 degrees.lengthwhich makes it different from a square.length = 5 ftwidth = 5 ftrectanglebrainly.com/question/20693059#SPJ4