Question Find the equation of the line that is perpendicular to y = -4x + 3 and contains the point (8, 1).

Answer: x-4y=8 Step-by-step explanation: y=mx+c comparing with given eq we get slope(m1)=-4 since both are prependicular m1×m2=-1 -4×m2=-1 m2=1÷4 eq:-y-y1=m2 (x-x1) y-1=(1÷4)(x-8) x-4y=4 Log in to Reply

y=1/4x-1 perpendicular means the y-intercept stays the same (so 3 stays), but the slope would be the opposite reciprocal of the original. the opposite of -4 is 4. opposite of negative=positive. the reciprocal of 4 is 1/4 so the new slope is 1/4 since we have a point, you plus everything on the point slope-form. y-y1=m(x-x1) (8,1)—> the 8 is x1 and the 1 is y1the slope is m so it’ll be y-1=1/4(x-8) solve. first distribute the 1/4 y -1=1/4x – 2 add 1 to both sides y= 1/4x – 1 Log in to Reply

Answer:x-4y=8

Step-by-step explanation:y=mx+c comparing with given eq

we get slope(m1)=-4

since both are prependicular

m1×m2=-1

-4×m2=-1

m2=1÷4

eq:-y-y1=m2 (x-x1)

y-1=(1÷4)(x-8)

x-4y=4

y=1/4x-1

perpendicular means the y-intercept stays the same (so 3 stays), but the slope would be the opposite reciprocal of the original.

the opposite of -4 is 4. opposite of negative=positive.

the reciprocal of 4 is 1/4

so the new slope is 1/4

since we have a point, you plus everything on the point slope-form.

y-y1=m(x-x1)

(8,1)—> the 8 is x1 and the 1 is y1

the slope is m

so it’ll be

y-1=1/4(x-8)

solve. first distribute the 1/4

y -1=1/4x – 2

add 1 to both sides

y= 1/4x – 1