Question Find the equation of the line that is perpendicular to y = -4x + 3 and contains the point (8, 1).
Answer: x-4y=8 Step-by-step explanation: y=mx+c comparing with given eq we get slope(m1)=-4 since both are prependicular m1×m2=-1 -4×m2=-1 m2=1÷4 eq:-y-y1=m2 (x-x1) y-1=(1÷4)(x-8) x-4y=4 Log in to Reply
y=1/4x-1 perpendicular means the y-intercept stays the same (so 3 stays), but the slope would be the opposite reciprocal of the original. the opposite of -4 is 4. opposite of negative=positive. the reciprocal of 4 is 1/4 so the new slope is 1/4 since we have a point, you plus everything on the point slope-form. y-y1=m(x-x1) (8,1)—> the 8 is x1 and the 1 is y1the slope is m so it’ll be y-1=1/4(x-8) solve. first distribute the 1/4 y -1=1/4x – 2 add 1 to both sides y= 1/4x – 1 Log in to Reply
Answer:
x-4y=8
Step-by-step explanation:
y=mx+c comparing with given eq
we get slope(m1)=-4
since both are prependicular
m1×m2=-1
-4×m2=-1
m2=1÷4
eq:-y-y1=m2 (x-x1)
y-1=(1÷4)(x-8)
x-4y=4
y=1/4x-1
perpendicular means the y-intercept stays the same (so 3 stays), but the slope would be the opposite reciprocal of the original.
the opposite of -4 is 4. opposite of negative=positive.
the reciprocal of 4 is 1/4
so the new slope is 1/4
since we have a point, you plus everything on the point slope-form.
y-y1=m(x-x1)
(8,1)—> the 8 is x1 and the 1 is y1
the slope is m
so it’ll be
y-1=1/4(x-8)
solve. first distribute the 1/4
y -1=1/4x – 2
add 1 to both sides
y= 1/4x – 1