Now we find the conditional probability P(S > 6 | neither die is a two)

⇒ P(S > 6 | neither die is a two) = P(S > 6 AND neither die is a two) ÷

(neither die is a two)

⇒ P(S > 6 | neither die is a two) = (17/36) / (25/36)

⇒ P(S > 6 | neither die is a two) = 17/25

Therefore, the conditional probability, in a single roll of two fair 6 sided dice, that the sum is greater than 6, given that neither die is a two : 17/25

conditional probability, in a single roll of two fair 6 sideddice, that the sum is greater than 6, given that neither die is a two : 17/25conditional probabilityis given by,probabilityof occurrence of event B, given that event A hasprobabilityof happening two events A and B at the same time.diceD1 and D2 are rolled once.dicebe d1 and d2 respectively.conditional probabilitythat the sum is greater than 6, given that neither die is a two.probabilityis 1/2.probabilityfor the sum is greater than 6 i.e., P(S > 6)probabilitythat neither die is a twoprobabilitythat the sum S > 6 AND neither die is a two.conditional probabilityP(S > 6 | neither die is a two)conditional probability, in a single roll of two fair 6 sideddice, that the sum is greater than 6, given that neither die is a two : 17/25probabilityhere: