Answers

1. To find the x- and y-intercepts of a line, we can set either the x-coordinate or the y-coordinate to 0 and solve for the other coordinate.

   For the first line, 5x + 17y = -25, we can find the x-intercept by setting y = 0:

   5x + 17(0) = -25

   5x = -25

   x = -5

   Therefore, the x-intercept of the line 5x + 17y = -25 is (-5, 0).

   To find the y-intercept, we can set x = 0:

   5(0) + 17y = -25

   17y = -25

   y = -25 / 17

   y = -1.47

   Therefore, the y-intercept of the line 5x + 17y = -25 is (0, -1.47).

   For the second line, 6x – 7y = -21, we can find the x-intercept by setting y = 0:

   6x – 7(0) = -21

   6x = -21

   x = -21 / 6

   x = -3.5

   Therefore, the x-intercept of the line 6x – 7y = -21 is (-3.5, 0).

   To find the y-intercept, we can set x = 0:

   6(0) – 7y = -21

   -7y = -21

   y = 21 / -7

   y = -3

   Therefore, the y-intercept of the line 6x – 7y = -21 is (0, -3).

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2. Answer:

   (0, -25/17)

   Step-by-step explanation:

   To find the x-intercept of a line, we need to set y equal to zero and solve for x. To find the y-intercept, we need to set x equal to zero and solve for y.

   For the line 5x + 17y = -25, setting y equal to zero gives us:

   5x + 17(0) = -25

   5x = -25

   x = -5

   Thus, the x-intercept is (-5, 0).

   Setting x equal to zero gives us:

   5(0) + 17y = -25

   17y = -25

   y = -25/17

   Thus, the y-intercept is (0, -25/17).

   Therefore, the x-intercept is (-5, 0) and the y-intercept is (0, -25/17).

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