Question Find the 1st term of an arithmetic sequence whose common difference is – 9 and whose 101st term is – 902.

Answer: a = -2 Step-by-step explanation: Tn = a+(n-1) * d -902 = a + (101-1) * -9 -902 = a – 900 a = -902 + 900 a = -2 Log in to Reply

Answer:Step-by-step explanation: