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1. The equation of variation in which y varies jointly as x and z and inversely as the product of w and p is y=0.5(xz/wp).

   Given that variable y varies jointly as x and z and inversely as the product of w and p,where y=7/28 where x=7,z=4,w=7 and p=8.

   We are required to find the equation of variation.

   To solve this problem we must apply the following procedure:

   1) We have that y varies jointly as x and z and inversely as the product of w and p. Therefore we can write the following equation,where k is the constant of proportionality:

   y=k(xz/wp)———-1

   Now we have to solve for the constant of proportionality as done under:

   k=ywp/xz————-2

   Using the values in equation 1.

   k=(7/28)(7)(8)/(7)(4)

   =0.5

   Using all the values in the equation 2.

   y=0.5(xz/wp)

   Hence the equation of variance is y=0.5(xz/wp).

   Question is incomplete.The following values should be included:

   y=7/28 where x=7,z=4,w=7 and p=8.

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