Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)

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1. Answer:

   y = -2/3x + 20/3

   Step-by-step explanation:

   2x + 3y = 6

   3y = -2x + 6

   y = -2/3x + 2

   y = -2/3x + b

   4 = -2/3(4) + b

   4 = -8/3 + b

   20/3 = b

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2. Answer:

   Answer:

   Step-by-step explanation:

   Slope of a line 2x+3y=6 is -2/3

   So line passing through (0,4) has same slope because both are parallel

   From slope intercept form we have

   Y-y1 =m(x-1)

   Y-4= -2/3(x-0)

   3Y-12 = -2x

   3Y+2x = 12

   Which is required equation of a line.

   Step-by-step explanation:

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