Answer: [tex]\displaystyle d = \sqrt{53}[/tex] General Formulas and Concepts: Pre-Algebra Order of Operations: BPEMDAS Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Algebra I Coordinates (x, y) Algebra II Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] Step-by-step explanation: Step 1: Define Point A(-4, 1) Point B(3, -1) Step 2: Find distance d Simply plug in the 2 coordinates into the distance formula to find distance d Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(3+4)^2+(-1-1)^2}[/tex] [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(7)^2+(-2)^2}[/tex] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{49+4}[/tex] [√Radical] Add: [tex]\displaystyle d = \sqrt{53}[/tex] Reply
Answer:
[tex]\displaystyle d = \sqrt{53}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Algebra I
Algebra II
Step-by-step explanation:
Step 1: Define
Point A(-4, 1)
Point B(3, -1)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d