Factor completely the given polynomial x(x + 20) + 11(x + 20) x(x + 20) + 11(x + 20)= August 17, 2021 by Dulcie Factor completely the given polynomial x(x + 20) + 11(x + 20) x(x + 20) + 11(x + 20)=
Answer: (x + 20)(x + 11) Step-by-step explanation: x(x + 20) + 11(x + 20) = Factor out the common factor of x + 20. = (x + 20)(x + 11) The binomials make it look complicated, but this is simpler than you think. Look at this simpler, but similar, example. Factor xy + 4y xy + 4y = You see clearly that y is a common factor, so you factor out y, and you get = y(x + 4) In your problem, you have x(x + 20) + 11(x + 20) = where (x + 20) is the common factor. You factor out the common factor, (x + 20). What is left? x + 11 as a factor, so you get (x + 20)(x + 11) Reply
Answer:
(x + 20)(x + 11)
Step-by-step explanation:
x(x + 20) + 11(x + 20) =
Factor out the common factor of x + 20.
= (x + 20)(x + 11)
The binomials make it look complicated, but this is simpler than you think.
Look at this simpler, but similar, example.
Factor xy + 4y
xy + 4y =
You see clearly that y is a common factor, so you factor out y, and you get
= y(x + 4)
In your problem, you have
x(x + 20) + 11(x + 20) =
where (x + 20) is the common factor.
You factor out the common factor, (x + 20). What is left? x + 11 as a factor, so you get
(x + 20)(x + 11)