Question

Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answers

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    The percent error between 75 and 80 is 6.667%
    Solution:
    Given: Accepted Value = 75 , Observed Value = 80
    Percent Error Formula
    Percent Error = | (Observed Value − Accepted Value) / Accepted Value | × 100  
    Substitute values into the formula and solve:
    Percent Error = | (80 − 75) / 75 | × 100  
    = | (5) / 75 | × 100  
    = | 0.067 | × 100  
    = 6.667% (three decimal places)
    Percent Error = 6.667%
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