Question Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answer: 0.8 Step-by-step explanation: 1. Subtract both equations 2. You will get your answer (Hope I’m right) Reply

Results The percent error between 75 and 80 is 6.667% Solution: Given: Accepted Value = 75 , Observed Value = 80 Percent Error Formula Percent Error = | (Observed Value − Accepted Value) / Accepted Value | × 100 Substitute values into the formula and solve: Percent Error = | (80 − 75) / 75 | × 100 = | (5) / 75 | × 100 = | 0.067 | × 100 = 6.667% (three decimal places) Percent Error = 6.667% https://goodcalculators.com/percent-error-calculator/ © 2015-2022 goodcalculators.com Reply

Answer:Step-by-step explanation: