Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?
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Answer:0.8Step-by-step explanation:1. Subtract both equations2. You will get your answer(Hope I’m right)
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ResultsThe percent error between 75 and 80 is 6.667%Solution:Given: Accepted Value = 75 , Observed Value = 80Percent Error FormulaPercent Error = | (Observed Value − Accepted Value) / Accepted Value | × 100Substitute values into the formula and solve:Percent Error = | (80 − 75) / 75 | × 100= | (5) / 75 | × 100= | 0.067 | × 100= 6.667% (three decimal places)Percent Error = 6.667%https://goodcalculators.com/percent-error-calculator/© 2015-2022 goodcalculators.com