Question

EMERGENCY PLS HELP 15 POINTS
Solve the following systems using the elimination method.
-8x+8y=24
8x-5y=0

Answers

  1. Answer:
    x=5, y=8
    Step-by-step explanation:
    In order to solve using elimination you have to “eliminate” one of the variables (get it?).
    The x values, -8x and 8x, can be eliminated by just adding them together (-8x+8x=0), sometimes you would need to multiply one of the variables to make it equal to the other.
    Now you have to add the y values together, (8y+ -5y= 3y) and lastly the 24 and 0 (24+0=24) which add to 24.
    You’re now left with 3y=24, in order to get rid of the coefficient, the number in front of y, you need to divide both terms by 3, (3y÷3=y) (24÷3=8) and finally you get y=8.
    You now need to plug in the y value into one of the original equations, for example 8x-5y=0 turns to -> 8x-5(8)=0. You multiple -5 by 8 to get -40
    8x-40=0
    Now to get the variable by itself you add 40 to both sides of the equation, removing -40 from the left side of the equal sign and bringing it to the right.
    8x=40
    Divide both terms by 8 to get x by itself
    x=5
    And there you go, x=5 and y=8.
    To doubly so make sure you got it right you could plug in the variables to the equation you didn’t use
    -8x+8y=24 -> -8(5)+8(8)=24
    -8(5)= -40
    8(8)= 64
    -40+64=24
    And doing 64-40 you get 24
    24=24
    Yup, checks out.

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