Question

EMERGENCY PLS HELP 15 POINTS
Solve the following systems using the elimination method.
-8x+8y=24
8x-5y=0

1. bonexptip

x= 5
y=8
the other person gave you the explanation

2. x=5, y=8
Step-by-step explanation:
In order to solve using elimination you have to “eliminate” one of the variables (get it?).
The x values, -8x and 8x, can be eliminated by just adding them together (-8x+8x=0), sometimes you would need to multiply one of the variables to make it equal to the other.
Now you have to add the y values together, (8y+ -5y= 3y) and lastly the 24 and 0 (24+0=24) which add to 24.
You’re now left with 3y=24, in order to get rid of the coefficient, the number in front of y, you need to divide both terms by 3, (3y÷3=y) (24÷3=8) and finally you get y=8.
You now need to plug in the y value into one of the original equations, for example 8x-5y=0 turns to -> 8x-5(8)=0. You multiple -5 by 8 to get -40
8x-40=0
Now to get the variable by itself you add 40 to both sides of the equation, removing -40 from the left side of the equal sign and bringing it to the right.
8x=40
Divide both terms by 8 to get x by itself
x=5
And there you go, x=5 and y=8.
To doubly so make sure you got it right you could plug in the variables to the equation you didn’t use
-8x+8y=24 -> -8(5)+8(8)=24
-8(5)= -40
8(8)= 64
-40+64=24
And doing 64-40 you get 24
24=24
Yup, checks out.