Question Dilate triangle ABC by a scale factor of 2 with a center of dilation of (2, 3). A(2, 5), B(-3, 3), C(2, -1)

Given the vertices of triangle ABC: A(2, 5), B(-3, 3), C(2, -1) Let’s dilate the triangle ABC by a scale factor of 2 with a center of dilation of (2, 3) Here, since we have a scale factor, k, of 2 and center of dilation (2, 3), apply the formula: (x’, y’) = k(x – a)+a, k(y – b)+ b Where: (a, b) is the center of dilation: (2, 3) (x, y) is the coordinate (x’ y’) is the new coordinate k is the sale factor = 2 Thus, we have the following: A(2, 5) ==> 2(2 – 2)+2, 2(5 – 3)+3 ==> 2(0)+2, 2(2)+3 ==> (2, 9) B(-3, 3) ==> 2(-3 – 2)+2, 2(3 – 3)+3 ==> 2(-5)+2, 2(0)+3 ==> (-8, 3) C(2, -1) ==> 2(2 – 2)+2, 2(-1 – 3)+3 ==> 2(0)+2, 2(-4)+3 ==> (2, -5) Therefore, the vertices of triangle ABC after the dilation are: A'(2, 9), B'(-8, 3), C'(2, -5) ANSWER: A'(2, 9), B'(-8, 3), C'(2, -5) Log in to Reply

Therefore, the vertices of triangle ABC after the dilation are:A'(2, 9), B'(-8, 3), C'(2, -5)ANSWER:A'(2, 9), B'(-8, 3), C'(2, -5)