determine the discount between the point(-4,2) and the line 4y=3×+6​

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1. Answer:

   d = 14/5

   Step-by-step explanation:

   The point (-4,2) means that;

   At x = -4, y = 2

   Now general form of a linear equation is;

   Ax + By + C = 0

   We are given;

   4y = 3x + 6​

   Rearranging to the form of a linear equation gives;

   3x – 4y + 6 = 0

   Thus, A = 3, B = -4 and C = 6

   Thus, at point (-4,2), distance between them is;

   d = (3(-4) – 4(2) + 6)/√(3² + (-4)²)

   d = -14/5

   We will take the absolute value.

   Thus; d = 14/5

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