Question

describe how light reflecting from a mirror can produce an image. In particular, explain how mirrors can produce images that are larger or smaller than life size, as well as upright or inverted.

Answers

  1. Answer:

    A larger image is produced when  d_i > d_o

    A smaller image is produced when d_i < d_o

    An upright image  is produced when m is positive

    An upright image  is produced when m is negative

    Explanation:

    The mirror equation is given as follows;

    \dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}

    m =-\dfrac{d_i}{d_o} = \dfrac{h_i}{h_o}

    For concave mirrors, f = focal length

    d_i = Image distance from the mirror (-ve d_i = Image is behind the mirror +ve d_i = Image is in front of the mirror)

    d_o = Object distance from the mirror (-ve d_o = Object is behind the mirror +ve d_o = Object is in front of the mirror)

    m = Magnification (-ve m = Inverted image +ve m = upright image)

    h_i = Image height

    h_o = Object height

    f = Focal length of the mirror

    To produce a larger image d_i > d_o

    To produce a smaller image d_i < d_o

    To produce an upright image, m should be positive hence, d_i will be negative or the image will appear behind the mirror

    To produce an inverted image, m should be negative hence, d_i will be positive or the image will form in front of the mirror.

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