Consider the two slope fields shown, in figures 1 and 2 below. On a print-out of these slope fields, sketch for each three solution curves to the differential equations that generated them. Then complete the following statements: For the slope field in figure 1. a solution passing through the point (0.-1) has slope. For the slope field in figure 1. a solution passing through the point (-2.2) has slope. For the slope field in figure 2. a solution passing through the point (1.-3) has slope For the slope field in figure 2. a solution passing through the point (0.4) has a slope.
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The slopes of the figures 1 , 2 & 3 are 0 , 1 & 1/3 respectively.Given, two figures with the lines passing through different pointswe have to find the slopes of different figures.Now, in figure 1 curve passes through (0 , -1)as, 2x + 2yy’ = 0y’ = -x/yy’ = -(0)/-1y’ = 0Now, in figure 2 curve passes through (-2 , 2)as, y ‘ = -x/yy’ = -(-2)/2y’ = 1In figure 3 curve passes through (1 , -3)as, y’ = -x/yy’ = -1/-3y’ = 1/3So, the slopes of the figures 1 , 2 & 3 are0 , 1 & 1/3 respectively.Hence, the slopes of the figures 1 , 2 & 3 are 0 , 1 & 1/3 respectively.Learn more about Differential Equations here https://brainly.com/question/1164377#SPJ4