Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value.

y=-x^2+4x+12

Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value.

y=-x^2+4x+12

Answer:x^2+4x+12=(x+3)^2+3

Step-by-step explanation:x^2+4x+12

(1/2×6)^2=(3)^2=9

x^2+4x+(3)^2-(3)^2+12

x^2+4x+9-9+12

(x+3)^2-9+12

(x+3)^2+3

hope I helped.