Casey buys sandwiches and bags of chips. Each sandwhich cost three times as much as a bag of chips.bshe bought 5 sandwiches for $6 each and spent $42. How many bags b did she buy?

Answers

Therefore, the number of bags of chips Casey buys if each sandwhich cost three times as much as a bag of chips is 6 bags of chips.

Equation

Cost of each bag of chips = y

Cost of sandwiches = 3y = $6

3y = $6

y = $6/2

y = $3

Number of sandwiches bought = 5

Number of bags of chips = x

Total spent = $42

Total spent = (Cost of each bag of chips × Number of bags of chips) + (Cost of sandwiches × Number of sandwiches bought)

42 = (y × x) + ($6 × 5)

42 = (2 × x) + 30

42 = 2x + 30

42 – 30 = 2x

12 = 2x

x = 12/2

x = 6bagsof chips

Therefore, the number of bags of chips Casey buys if each sandwhich cost three times as much as a bag of chips is 6 bags of chips

bags of chipsCasey buys if eachsandwhichcost three times as much as a bag of chips is6 bagsof chips.## Equation

y = $3x = 6bagsofchipsnumberof bags of chips Casey buys if each sandwhich cost three times as much as a bag of chips is6 bags of chipsequation: