Question

Can anyone help me with this?

Putting the question into an online calculator gives me 4 Rad x. but what are the steps to solve it?

Simplify the following expression:
(x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6

Show all work to recive full credit.

1. niczorrrr
The simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)

### How to simplify the expression?

The algebraic statement is given as:
(x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6
Rewrite the algebraic statement as:
[(x^0 y^2/3 z^-2y)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the like factors
[(x^0 y^(2/3+1) z^-2)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the sum
[(x^0 y^5/3 z^-2)^2/3]/[(x^2 z^1/2)^-6]
Expand the exponents
[(x^(0*2/3) y^(5/3 * 2/3)z^(-2*2/3)]/[(x^(2*-6) z^(1/2*-6)]
Evaluate the products
[(x^0 y^(10/9) z^(-4/3)]/[(x^(-12) z^(-3)]
Apply the quotient law of indices
x^(0+12) y^(10/9) z^(-4/3+3)
Evaluate the sum of exponents
x^(12) y^(10/9) z^(-1/3)
Hence, the simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)