Calculate the centripetal force on the end of a 100 m (radius) massless cable that is rotating at 0.5 rev/s. Assume the mass on the end of the cable is 4 kg.

Question

thanhcong · Answer

Answer:   F_{cp}=3947.84N     Explanation:   From the formula for centripetal force and acceleration we can deduce that:  F_{cp}=ma_{cp}=m frac{v^2}{r}=m frac{(r omega)^2}{r}=mr omega^2=mr omega^2  Since one revolution is 2 pi   rad, 0.5 revolutions are  pi  rad, so we have:  F_{cp}=(4kg)(100m)( pi  rad/s)^2=3947.84N

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