bryson recorded the following ages of family members at his grandmother at his grandmothers birthday party:75,28,16,8,4,12,80,93,37 and 50. what is the mean absolute deviation of the ages of the ages of the people at the party?

Answers

The mean absolute deviation of the ages of the ages of the people at the party is 32.70

What is the significance of the mean absolute deviation?

The mean absolute deviation measures how far each age is from the mean

The first step is to determine the mean of the data distribution

mean=(75+28+16+8+4+12+80+93+37+50)/10

mean=40.30

We need to determine the difference between each age and the mean age disregarding negative signs

sum of distances from the mean=(75-40.30)+(28-40.30)+(16-40.30)+(8-40.30)+(4-40.30)+(12-40.30)+(80-40.30)+(93-40.30)+(37-40.30)+(50-40.30)

sum of distances from the mean=34.70+12.30+24.30+32.30+36.30+28.30+39.70+52.70+56.70+9.70

sum of distances from the mean=327.00

MAD=327.00/10

MAD=32.70

On the average, each age is 32.70 years away from the mean age of 40.30

What is the significance of the mean absolute deviation?mean absolute deviationmeasures how far each age is from the meanMAD=327.00/10MAD=32.70mean absolute deviationon:https://brainly.com/question/3998118