Bob is 25 years younger than his father and 27 years older than his son. Together,
the sum of their ages is 100. What is each
of their ages?
Question
Question
Bob is 25 years younger than his father and 27 years older than his son. Together,
the sum of their ages is 100. What is each
of their ages?
Answer:
Bob son is 7 years
Father’s age is 59 years
Bob is 34 years
Step-by-step explanation:
Bob age be x
Father age be y
Son’s age be w
Bob is younger means father is older;
y = 25+x ; x = y -25
x = 27 + w
y-25 = 27+w
y = 27+25+w = 52 +w
x + y + w = 100
27+w + 52+w +w = 100
79+3w = 100
3w = 100-79 = 21
w = 21/3 = 7 years
y = 52+w = 52+7 = 59 years
x = 27 + w = 27 +7 = 34 years
Answer:
Bob = 34, father = 59, son = 7
Step-by-step explanation:
Use a system of equations:
Bob = x
Father = x + 25
Son = x – 27
Add them all together, set equal to 100 and solve:
x + x + 25 + x -27 = 100
3x – 2 = 100
3x = 102
x = 34 (bob)
Then plug x back into the equations to solve for father and son age:
34 + 25 = 59 (father)
34 – 27 = 7 (son)
Then you can check your work by adding 34+59+7 and you get 100.