Question (b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity?

Answer: The time taken is missing in the question. The time is 18 minutes. The answer is 34.3 km/hr Explanation: Average velocity is the speed or the velocity which is required to cover a distance in a time interval. The time taken is = 18 min = 18/60 hours The distance from the university to her home is = 10.3 km Therefore, the average velocity is = displacement/time taken = 10.3 / (18/60) km/hr = 34.3 km/hr Hence, the average velocity is 34.3 km/hr Log in to Reply

Answer:The time taken is missing in the question. The time is 18 minutes.

The answer is 34.3 km/hrExplanation:Average velocity is the speed or the velocity which is required to cover a distance in a time interval.

The time taken is = 18 min

= 18/60 hours

The distance from the university to her home is = 10.3 km

Therefore, the average velocity is = displacement/time taken

= 10.3 / (18/60) km/hr

= 34.3 km/hr

Hence, the average velocity is 34.3 km/hr