Question b. 48C. 365. (x+4), (x+12), (x-1) and (x+5) are in proportion. Find the value of x.b. 12a. 15c. 16d., 20

Answer: c Step-by-step explanation: Expressing the proportion in fractional form , that is [tex]\frac{x+4}{x+12}[/tex] = [tex]\frac{x-1}{x+5}[/tex] ( cross- multiply ) (x + 4)(x + 5) = (x + 12)(x – 1) ← expand both sides using FOIL x² + 9x + 20 = x² + 11x – 12 ← subtract x² + 9x from both sides 20 = 2x – 12 ( add 12 to both sides ) 32 = 2x ( divide both sides by 2 ) 16 = x → c Log in to Reply

Answer:c

Step-by-step explanation:Expressing the proportion in fractional form , that is

[tex]\frac{x+4}{x+12}[/tex] = [tex]\frac{x-1}{x+5}[/tex] ( cross- multiply )

(x + 4)(x + 5) = (x + 12)(x – 1) ← expand both sides using FOIL

x² + 9x + 20 = x² + 11x – 12 ← subtract x² + 9x from both sides

20 = 2x – 12 ( add 12 to both sides )

32 = 2x ( divide both sides by 2 )

16 = x → c