Question At what frequency should a 200-turn, flat coil of cross sectional area of 300 cm2 be rotated in a uniform 30-mT magnetic field to have a maximum value of the induced emf equal to 8.0 V

Answer: The frequency of the coil is 7.07 Hz Explanation: Given; number of turn of the coil, N = 200 turn area of the coil, A = 300 cm² = 0.03 m² magnitude of magnetic field, B = 30 mT = 0.03 T maximum value of induced emf, E = 8 V The maximum induced emf in the coil is given by; E = NBAω E = NBA(2πf) [tex]f = \frac{E_{max}}{2\pi*NBA}[/tex] where; f is the frequency of the coil [tex]f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz[/tex] Therefore, the frequency of the coil is 7.07 Hz Log in to Reply

Answer:The frequency of the coil is

7.07 HzExplanation:Given;

number of turn of the coil, N = 200 turn

area of the coil, A = 300 cm² = 0.03 m²

magnitude of magnetic field, B = 30 mT = 0.03 T

maximum value of induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

E = NBA(2πf)

[tex]f = \frac{E_{max}}{2\pi*NBA}[/tex]

where;

f is the frequency of the coil

[tex]f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz[/tex]

Therefore, the frequency of the coil is

7.07 Hz