At one university, the mean distance commuted to campus by students is 19.0 miles, with a standard deviation of 4.2 miles. Suppose

Question

At one university, the mean distance commuted to campus by students is 19.0 miles, with a standard deviation of 4.2 miles. Suppose that the commute distances are normally distributed. Complete the following statements. (a) Approximately 95% of the students have commute distances between miles and miles. (b) Approximately 7 miles and 31.6 miles. of the students have commute distances between 6.4

MichaelMet · Answer

The  average  commute for 95% of the students is between 19.0 and 4.2 miles.    The average distance is 19 miles.  Therefore, the standard deviation is 4.2 miles.  A) 2.7 = 19 - a(4.2)  where;  a deviates from the mean by a certain number of standard deviations. Thus;  a = (19 - 2.7) ÷ 4.2  a = 3  In a  normal distribution , 3 standard deviations from the mean indicate that 95% of the data falls within that range.  B) The data are 2 standard deviations apart from the mean at the 95%  confidence level . Thus;  CI = 19 ± 2(4.2)  CI = (18 - 10.2) OR (18 + 10.2)  CI = (7.8, 28.2)    Learn more about  confidence intervals  at  https://brainly.com/question/17097944    #SPJ4

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