An open organ pipe emits E (330 Hz ) when the temperature is 26 ∘C. The speed of sound in air is v≈(331+0.60T)m/s, where T is the temperature in ∘C. Determine the length of the pipe.

Answer:

0.525 m

Explanation:

From the question,

In an open pipe,

v = λf………………. Equation 1

Where v = speed of sound in the pipe, f = frequency, λ = wave length.

Answer:0.525 mExplanation:From the question,

In an open pipe,

v = λf………………. Equation 1

Where v = speed of sound in the pipe, f = frequency, λ = wave length.

But,

λ = 2l……………. Equation 2

Where l = length of the pipe

Substitute equation 2 into equation 1

v = 2lf………….. Equation 3

make l the subject of the equation

l = v/2f…………. Equation 4

Given:

v ≈ (331+0.60T) m/s at T = 26°C

v ≈ (331+0.60×26) ≈ 346.6 m/s

f = 330 Hz.

Substitute these values into equation 4

l = 346.6/(2×330)

l = 346.6/660

l = 0.525 m

Hence the length of the pipe is 0.525 m