Question An object is launched horizontally at a velocity of 19 m/s from the top of a building. It falls vertically a distance of 24m before it reaches the ground. How long does this projectile travel before reaching the ground?

Answer: 2.2 s Explanation: His vertical initial velocity u =0 vertical displacement h = 24 m . vertical acceleration g = 9.8 m /s² h = ut + 1/2 gt² 24 = 1/2 x 9.8 x t² t = 2.2 s . Time of fall = 2.2 s Log in to Reply

Answer:2.2 s

Explanation:His vertical initial velocity u =0

vertical displacement h = 24 m .

vertical acceleration g = 9.8 m /s²

h = ut + 1/2 gt²

24 = 1/2 x 9.8 x t²

t = 2.2 s .

Time of fall = 2.2 s