An electric stove with four burners and an oven is used in preparing a meal as follows. Burner 1: 20 minutes Burner 2: 40 minutes Burner 3: 15 minutes Burner 4: 45 minutes Oven: 30 minutes If each burner is rated at 1.1 kW and the oven at 2.5 kW, and electricity costs 12 cents per kWh, calculate the cost of electricity used in preparing the meal. slader
Answer:
41.4 cents
Explanation:
The Quantity of heat used up is expressed as H = Power * Time
For Burner 1;
Power rating= 1.1kW
Time used = 20mins = (20/60)hr
Time (in hour) = 1/3 hr
H = 1.1* 1/3
H = 11/10*1/3
H = 11/30kWh
For Burner 2;
Power rating= 1.1kW
Time used = 40mins = (40/60)hr
Time (in hour) = 2/3 hr
H = 1.1* 2/3
H = 11/10*2/3
H = 22/30kWh
H = 11/15 kWh
For Burner 3;
Power rating= 1.1kW
Time used = 15mins = (15/60)hr
Time (in hour) = 1/4 hr
H = 1.1* 1/4
H = 11/10*1/4
H = 11/40kWh
For Burner 4;
Power rating= 1.1kW
Time used = 45mins = (45/60)hr
Time (in hour) = 3/4 hr
H = 1.1* 3/4
H = 11/10*3/4
H = 33/40kWh
For Oven;
Power rating= 2.5kW
Time used = 30mins = (30/60)hr
Time (in hour) = 1/2 hr
H = 2.5* 1/2
H = 25/10*1/2
H = 25/20kWh
H = 5/4 kWh
Total Quantity of energy used = 11/30+11/15+11/40+33/40+5/4
Total Quantity of energy used = (44+88+33+99+150)/120
Total Quantity of energy used = 414/120
Total Quantity of energy used = 3.45kWh
If 1kWh costs 12 cents
3.34kWh will costs (12*3.45)cents
3.34kWh will cost 41.4cents
Hence the cost of electricity used in preparing the meal is 41.4 cents