An egg is dropped from a treehouse and takes 1.5 seconds to reach the ground. We can ignore air resistante What is the egg’s displacement?

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1. Answer:

   d = -11.025 m

   Explanation:

   Given that,

   An egg is dropped from a treehouse and takes 1.5 seconds to reach the ground. We need to find the egg’s displacement. It can be calculated using second equation of motion as follows :

   [tex]s=ut+\dfrac{1}{2}at^2[/tex]

   u is initial speed, the initial speed of egg is 0 as it was at rest initially.

   a = -g (as the stone is coming downward direction)

   t is time.

   si is egg’s displacement

   [tex]s=0-\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 9.8\times 1.5^2\\\\d=-11.025[/tex]

   -ve sign shows the displacement of the egg in opposite direction of its motion and its magnitude is 11.025 meters.

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