Question

An eagle is flying horizontally at a speed of 4.6 m/s when the fish in her talons wiggles loose and falls into the lake 4.2 m below. Calculate the vertical component of the velocity of the fish relative to the water when it hits the water.

Answers

  1. Answer:

    v = 9.07 m/s

    the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s

    Explanation:

    Given;

    An eagle is flying horizontally at a speed of 4.6 m/s

    Initial horizontal velocity uh = 4.6 m/s

    Initial vertical velocity uy = 0

    Height to fall d = 4.2 m

    Acceleration due to gravity g = 9.8 m/s^2

    The final vertical velocity of the fish when it hits the water can be calculated using the equation of motion;

    v^2 = u^2 + 2as

    v^2 = uy^2 + 2gd

    uy = 0

    v^2 = 2gd

    v = √(2gd)

    Substituting the given values;

    v = √(2×9.8×4.2)

    v = 9.073036977771 m/s

    v = 9.07 m/s

    the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s

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