Question An atom of gold has a diameter of 0.000000144 mm. What is another way to represent the diameter of an atom of gold? 1.44 x 10-6 mm 1.44 x 10-9 mm 1.44 x 107 mm 1.44 x 108 mm

The another way to represent the diameter of an atom of gold is 1.44 x 10⁻⁷mm. How to change the number in order of 10 to the power of something? To change the number in order of 10 to the power of something we simply find the decimal place and count the number of ‘0’ after the decimal place. For example: 0.00044001 mm in 10 to the power of something will be Here 3 zeros ( 0 ) and one ‘4’ after the decimal place so, we multiply and divide the given number by 10 ⁴. now, ( 0.00044001 x 10 ⁴) / 10 ⁴ such that decimal shift its position by 4, now, the number becomes 4.44001 / 10 ⁴ then, the answer will be 4.44001 x 10⁻⁴ We have given the diameter of an atom of gold is 0.000000144 mm here 6 zeros ( 0 ) and one ‘1’ after the decimal place so, we multiply and divide the given number by 10⁷. now, ( 0.000000144 x 10⁷ ) / 10⁷ such that decimal shifts its position by 7 after getting multiplied by 10⁷. now, the number becomes ( 1.44 ) / 10⁷ then, the answer will be 1.44 x 10⁻⁷. Hence, The another way to represent the diameter of an atom of gold is 1.44 x 10⁻⁷mm. Learn more about “Decimal Places in a number” from here: https://brainly.com/question/50455 #SPJ9 Reply

diameterof an atom of gold is## How to change the number in order of 10 to the power of something?

decimal placeand count the number of ‘0’ after the decimal place.atom of goldis 0.000000144 mmmultiplyanddividethe given number by 10⁷.diameterof an atom of gold isDecimal Places in a number” from here: https://brainly.com/question/50455