Question

Aakesh has two bags of marbles. The first bag contains 6 red marbles, 4 blue
marbles, and 5 green marbles. The second bag contains 3 red marbles, 1 blue
marble, and 5 green marbles. Aakesh will randomly select one marble from
each bag.
What is the probability that Aakesh will select a green marble from each bag?

A. 4/9

B.1/3

C. 5/9

D. 5/27

1. The answer for the 1st bag is option B = 1/3
The answer for the 2nd bag is option C = 5/9
Number of marbles in 1st bag – 15 (6 red, 4 blue & 5 green)
Number of marbles in 2nd bag – 9 (3 red, 1 blue & 5 green)
The formula of probability = Total number of events in the outcome /total number of outcomes.
Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)
That is 5/15=1/3
Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)
That is 5/9
To know more about probability go to –  https://brainly.in/question/17157610?msp_poc_exp=6

2. •ω• Hewo fren!
C.) 5/9
☆☆●◉✿Step-by-step explanation:✿◉●☆☆
First we must figure out how many marbles we have in total.
Meaning we will add all of the marbles together in bag one and then bag two.
Bag one: 6+4+5= 15
Bag two: 3+1+5= 9
Total= 24 marbles
Now we will try and figure out how many greens are in the total amount of marbles.
Amount of green marbles in bag one: 5
Amount of green marbles in bag two: 5
Total green marbles: 10
The third and final step!
10/24 is the amount of green marbles so the answer is C!