Question

Aakesh has two bags of marbles. The first bag contains 6 red marbles, 4 blue
marbles, and 5 green marbles. The second bag contains 3 red marbles, 1 blue
marble, and 5 green marbles. Aakesh will randomly select one marble from
each bag.
What is the probability that Aakesh will select a green marble from each bag?

A. 4/9

B.1/3

C. 5/9

D. 5/27

Answers

  1. The answer for the 1st bag is option B = 1/3
    The answer for the 2nd bag is option C = 5/9
    Number of marbles in 1st bag – 15 (6 red, 4 blue & 5 green)
    Number of marbles in 2nd bag – 9 (3 red, 1 blue & 5 green)
    The formula of probability = Total number of events in the outcome /total number of outcomes.
    Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)
    That is 5/15=1/3
    Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)
    That is 5/9
    To know more about probability go to –  https://brainly.in/question/17157610?msp_poc_exp=6

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  2. •ω• Hewo fren!
    ☆☆●◉✿ Answer:✿◉●☆☆
    C.) 5/9
    ☆☆●◉✿Step-by-step explanation:✿◉●☆☆
    First we must figure out how many marbles we have in total.
    Meaning we will add all of the marbles together in bag one and then bag two.
    Bag one: 6+4+5= 15
    Bag two: 3+1+5= 9
    Total= 24 marbles
    Now we will try and figure out how many greens are in the total amount of marbles.
    Amount of green marbles in bag one: 5
    Amount of green marbles in bag two: 5
    Total green marbles: 10
    The third and final step!
    10/24 is the amount of green marbles so the answer is C!

    Hope I helped~! >w<

    →⇒brainliest please? ∑(OΔO )♥♥︎

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