A woman who has a mass 50kg is wearing high heel shoes. The area of each heel in contact with the floor is 0.45 cm 2 . What is the pressure exerted by the woman on the floor if A. she stands on the 2 heels. B. she stands on 1 heel only.

Answer:

Explanation:

Pressure is defined as the ratio of force per unit area of a body

Pressure = Force/Area

a) Given mass of the woman = 50kg

Force exerted by the woman = 50×9.8

= 490N

Area of each each heel in contact with the floor = 0.45 cm² = 0.45×0.01m×0.01m = 0.000045m²

Pressure exerted by the woman standing on her two heels

= 490/2(0.000045){note that the area doubled)

= 5.44×10^6kg/m²

b) ,Pressure exerted if she stands on one heel only = 490N/0.000045 = 10.89×10^6N/m²

Answer:

Explanation:

Pressure is defined as the ratio of force per unit area of a body

Pressure = Force/Area

a) Given mass of the woman = 50kg

Force exerted by the woman = 50×9.8

= 490N

Area of each each heel in contact with the floor = 0.45 cm² = 0.45×0.01m×0.01m = 0.000045m²

Pressure exerted by the woman standing on her two heels

= 490/2(0.000045){note that the area doubled)

= 5.44×10^6kg/m²

b) ,Pressure exerted if she stands on one heel only = 490N/0.000045 = 10.89×10^6N/m²