A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of the wire and the current I through it if the wire has the following resistances?

a) 1.0Ω

b) 2.0Ω

c) 3.0Ω

a) 1.0Ω

b) 2.0Ω

c) 3.0Ω

Answer:Potential difference = 6.0 V

I for 1.0Ω = 6 A

I for 2.0Ω = 3 A

I for 3.0Ω = 2 A

Explanation:Potential difference (ΔV) = Current (I) x Resistance (R)

The potential difference is constant and equals 6.0 V, hence;

I = ΔV/R

When R = 1.0, I =6/1 = 6 amperes

When R = 2.0, I = 6/2 = 3 amperes

When R = 3.0, I = 6/3 = 2 amperes

The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.