A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of the wire and the current I through it if the wire has the following resistances?
a) 1.0Ω
b) 2.0Ω
c) 3.0Ω
Question
Answer:
Potential difference = 6.0 V
I for 1.0Ω = 6 A
I for 2.0Ω = 3 A
I for 3.0Ω = 2 A
Explanation:
Potential difference (ΔV) = Current (I) x Resistance (R)
The potential difference is constant and equals 6.0 V, hence;
I = ΔV/R
When R = 1.0, I =6/1 = 6 amperes
When R = 2.0, I = 6/2 = 3 amperes
When R = 3.0, I = 6/3 = 2 amperes
The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.