A wire carries a current of 4 A travelling to the left (-x direction). It is placed in a constant magnetic field of magnitude 0.05 T, pointing upward ( z direction). a. If 25 cm of the wire is in the magnetic field, what is the force on the current
Question
Answer:
0.05 N
Explanation:
Data provided in the question
The Wire carries a current of 4A to the left direction
The constant magnetic field of magnitude = 0.05 T
Pointing upward i.e Z direction
The wire is in the magnetic field = 25 cm
Based on the above information, the force on the current is
[tex]= Current \times constant\ magnetic\ field\ of\ magnitude \times magnetic\ field[/tex]
[tex]= 4 \times 0.05 \times 0.25[/tex]
= 0.05 N
The direction will be the negative Y direction