Question

A wire carries a current of 4 A travelling to the left (-x direction). It is placed in a constant magnetic field of magnitude 0.05 T, pointing upward ( z direction). a. If 25 cm of the wire is in the magnetic field, what is the force on the current

Answers

  1. Answer:

    0.05 N

    Explanation:

    Data provided in the question

    The Wire carries a current of 4A to the left direction

    The constant magnetic field of magnitude = 0.05 T

    Pointing upward i.e Z direction

    The wire is in the magnetic field = 25 cm

    Based on the above information, the force on the current is

    = Current \times constant\ magnetic\ field\ of\ magnitude \times magnetic\ field

    = 4 \times 0.05 \times 0.25

    = 0.05 N

    The direction will be the negative Y direction

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