Question a) What is the peak value of the voltage? b) What is the RMS value of the voltage? c) What is the angular frequency for this voltagesignal?

Answer: Check answer in below explanation Explanation: Peak value: It is the maximum value which is attained by alternating voltage. It is also known as crest value. It is represented by Vm. Equation of alternating voltage is V=Vm Sinωt; Where Vm is the Peak value of voltage RMS value: It is the square mean root of instantaneous value of voltage.It is represented by Vrms. Vrms is given by Vrms=[tex]\sqrt{\frac{1}{T} \int\limits^T_0 {V^2} \, dt}[/tex]; Vrms=[tex]\sqrt{\frac{1}{T} \int\limits^T_0 {Vm^2*sin^2wt} \, dt}[/tex]; Finallly, Vrms=Vm/(√2); Angular frequency for this voltage signal: It describe how the fast object is moving.It is represented by ω.and ω is Given by ω=2*π*f; Where f is simple frequency. Log in to Reply

Answer:Check answer in below explanationExplanation:Peak value:It is the maximum value which is attained by alternating voltage. It is also known as crest value. It is represented by Vm.

Equation of alternating voltage is

V=Vm Sinωt;

Where

Vmis the Peak value of voltageRMS value:It is the square mean root of instantaneous value of voltage.It is represented by Vrms.

Vrms is given by

Vrms=[tex]\sqrt{\frac{1}{T} \int\limits^T_0 {V^2} \, dt}[/tex];

Vrms=[tex]\sqrt{\frac{1}{T} \int\limits^T_0 {Vm^2*sin^2wt} \, dt}[/tex];

Finallly,

Vrms=Vm/(√2);

Angular frequency for this voltage signal:It describe how the fast object is moving.It is represented by ω.and ω is

Given by

ω=2*π*f;

Where f is simple frequency.