A uniform electric field of magnitude 4.1 ✕ 105 n/c points in the positive x direction. find the change in electric potential energy of a +4.9 µc charge as it moves from the origin to each of the points given below.
Question
Question
A uniform electric field of magnitude 4.1 ✕ 105 n/c points in the positive x direction. find the change in electric potential energy of a +4.9 µc charge as it moves from the origin to each of the points given below.
Answer:
2.009N
Explanation:
Force on a charge is equal to the product of the charge ans electric field intensity of the charge.
F = qE
q = 4.9E-6C
E = 4.1E5 N/C
F = qE
F = 4.9E-6 * 4.1E5
F = 2.009N