Question

A trebuchet launches a projectile on a parabolic arc from a height of 47 feet at a velocity of 40 ft/s.

Using the function h(t) = -16t^2 + vt + h0, determine when the projectile will first reach a height of 60 feet and how many seconds later it will again be at 60 feet.

Answers

  1. Answer:
    First at
    5/4 +(√3)/2s
    then at
    5/4 -(√3)/2
    Step-by-step explanation:
    h(t) = -16t^2 + 40t + 47 = 60
    so all we need to do it find the solution of the equation
    so 16t^2 – 40t + 13 = 0
    and as we know
    root = (-b+-√(b^2-4ac))/2a
    so
    root = 5/4 +-(√3)/2

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