A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of radius 1.50 m a

Question

A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of radius 1.50 m at an angular speed of 6.00 rad/s. As the superhero swings the hammer, she then ascends vertically at a constant 2.00 m/s. What is the speed of the end of the hammer relative to the ground?

in progress 0
Diễm Kiều 4 years 2021-07-19T15:16:20+00:00 1 Answers 103 views 0

Answers ( )

  1. lethu
    0
    2021-07-19T15:17:22+00:00
    Reply

    Answer: 9.22 m/s

    Explanation:

    Given

    Radius of circular path, r = 1.5 m

    Angular speed of hammer, w = 6 rad/s

    Vertical component of speed, v(v) = 2 m/s

    First, the horizontal component of speed is given by

    v(h) = wr

    v(h) = 1.5 * 6

    v(h) = 9 m/s

    Now, the speed of the hammer relative to the ground would be gotten if we find the resultant between both the horizontal and vertical component

    v = √[v(h)² + v(v)²]

    v = √(9² + 2²)

    v = √(81 + 4)

    v = √85

    v = 9.22 m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )