A steel bullet (66.45g) located 103.15 cm above the ground is shot in the horizontal direction. It travels 360.25 cm in the horizontal direc

Question

A steel bullet (66.45g) located 103.15 cm above the ground is shot in the horizontal direction. It travels 360.25 cm in the horizontal direction before it hits the ground. Calculate the momentum of the steel ball in the horizontal direction. Enter your results using the measured units, i.e., grams, centimeters and seconds. Use scientific notation for this calculation.

dangkhoa · Answer

Answer:    The answer is ' 4950  frac{g  cm }{s} '    Explanation:    Consider vertical component of motion:      to s_y=u_yt+  frac{1}{2} at^2    1.0315=0+ frac{1}{2}  times 9.81  times t^2    1.0315= frac{1}{2}  times 9.81  times t^2    1.0315=4.905  times t^2    t^2=  frac{1.0315}{4.905}    t=0.207059711           Considering the horizontal components:       to v_x=x times t        =03.6025  times 0.207059711    =0.745  frac{m}{s}     to p=mv    =66.45  times0.745  times 10^2    =4950    frac{g  cm }{s}

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