A spot of paint on a bicycle tire moves in a circular path of radius 0.33 m.
When the spot has traveled a linear distance of 1.76m , through what angle has the tire rotated?
Question
Question
A spot of paint on a bicycle tire moves in a circular path of radius 0.33 m.
When the spot has traveled a linear distance of 1.76m , through what angle has the tire rotated?
Answer:
305.5°
Explanation:
1.76 = (theta/360) × 2 × pi × 0.33
theta/360 = 0.8488263632
theta = 305.5774907