A solid cube of material is 1.50 cm on the edge. It submerged totally in oil of ρ = 820 kg/m3 .Find the buoyancy force of the material.
Question
Question
A solid cube of material is 1.50 cm on the edge. It submerged totally in oil of ρ = 820 kg/m3 .Find the buoyancy force of the material.
Answer:
0.027 N
Explanation:
From the question,
According to Archimedes principle,
The buoyancy force on the material = weight of oil displaced by the solid cube = Upthrust on the solid cube.
Applying,
U =ρ×V×g……………. Equation 1
Where U = Upthrust on the solid cube, ρ = density of oil, V = Volume of the solid cube, g = acceleration due to gravity
But,
V = l³……………. Equation 2
Substitute equation 2 into equation 1
U = gρl³………….. Equation 3
Given: ρ = 820 kg/m³, l = 1.50 cm = 0.015 m
Constant: g = 9.8 m/s²
Substitute these values into equation 3
U = 820×0.015³×9.8
U = 0.027 N