A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force on the skydiver?
A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force on the skydiver?
Answer:
497.6 N
Explanation:
From the question,
The net force on the skydiver = weight of the skydiver- the resistive force of air
F’ = W-F…………………. Equation 1
Where W = weight of the skydiver, F = resistive force of air.
But,
W = mg……………. Equation 2
Where m = mass of the skydiver, g = acceleration due to gravity.
Substitute equation 2 into equation 1
F’ = mg-F………… Equation 3
Given: m = 87 kg, F = 355 N, g = 9.8 m/s²
Substitute these values into equation 3
F’ = 87(9.8)-355
F’ = 852.6-355
F’ = 487.6 N
Answer:
498 N down
Explanation: